ACT Math · High-Frequency Domain (12–14 Questions, ~23% of Math Score)

Plane Geometry & Triangle Relationships

Key ACT Geometry Formula Rule

Unlike the SAT, the ACT does NOT provide a formula reference sheet at the start of the Math section! You must memorize: (1) Area of a triangle (½bh), (2) Pythagorean theorem (a² + b² = c²), (3) Special right triangles (30°-60°-90° and 45°-45°-90°), and (4) Similar figure area ratio (k² = (s&sub1; / s&sub2;)²).

1. The Four Non-Negotiable ACT Geometry Rules

Geometry accounts for nearly a quarter of all ACT Math points. The test questions emphasize these core relationships:

Rule 1

Similar Figures & Area Ratios

If two shapes are similar with linear scale factor k, their perimeter ratio is k, their area ratio is k², and their volume ratio is k³.

Rule 2

Parallel Lines & Transversals

When parallel lines are cut by a transversal, all acute angles are equal, all obtuse angles are equal, and any acute + obtuse angle = 180°.

Rule 3

Special Right Triangles

30°-60°-90° sides are x, x√3, 2x. 45°-45°-90° sides are x, x, x√2. Memorize these to avoid slow trigonometry.

Rule 4

Circle Arcs & Sectors

A circle slice is simply a fraction: (θ / 360°) = (Arc Length / 2πr) = (Sector Area / πr²).

ACT Trap: Figures Are "Not Necessarily Drawn to Scale"

Unless an ACT problem explicitly specifies that a diagram is drawn to scale, never assume an angle is 90° or that two lines are parallel based purely on visual inspection. Look for explicit perpendicular symbols (⊥), angle arc values, or given parallel arrows (||).

2. Rapid Triangle Angle Rules

Worked Official-Style ACT Example

Question: In a circle with center O, radius r = 12 cm, and central angle ∠AOB = 60°, what is the area, in square centimeters, of sector AOB?

A) 12π
B) 24π
C) 48π
D) 144π
View Step-by-Step Solution

Correct Answer: B

Step 1: Calculate Total Circle Area: Area = πr² = π(12²) = 144π.

Step 2: Find Sector Fraction: 60° / 360° = 1/6.

Step 3: Multiply: Sector Area = 1/6 × 144π = 24π square centimeters.

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